Loads
and nominal operational life of the load carriage
(Example: type AZ 2005)
Determination of the load acting on the carriage with
modified running capacity, e.g. running capacity of
5·107 m
For Ln = 5·107 m, the correction
value K is 1.6 according to the diagram
| FY |
= |
2200 |
N |
:
1.6 = |
1375.0 |
N |
| FZ |
= |
1200 |
N |
:
1.6 = |
750.0 |
N |
| MX |
= |
84 |
Nm |
:
1.6 = |
52.5 |
Nm |
| My |
= |
124 |
Nm |
:
1.6 = |
77.5 |
Nm |
| MZ |
= |
212 |
Nm |
:
1.6 = |
132.5 |
Nm |
Calculation of the nominal operational life Lh
in hours:
| Ln |
=
running capacity (107m) |
| s |
=
traversing distance (m) |
| f |
=
number of traverses per min |
e.g.
| Ln |
=
5 · 107 |
| s |
=
3 m |
| f |
=
60 (at 3m/s) |
